WebEx-5 Prove that the circle x2 + y2 + 2ax + c2 = 0 and x2 + y2 + 2by + c2 = 0 touche each other 1 1 1 if 2 2 2 a b c [Sol. Subtract to get common tangent and drop perpendicular … WebThen the new equation is : (A) x2 + y2 = 9 (B) x2 + y2 = 49 4 (C) x2 + y2 = 81 16 (D) none of ... β = ± 1 (D) α = ± 1, β = 1 Q.2 The axes are translated so that the new equation of the circle x²+y²– 5x+ 2y – 5 = 0 has no first degree terms. Then the new equation is : (A) x2 + y2 = 9 (B) x2 + y2 = 49 4 (C) x2 + y2 = 81 16 (D) ...
If two circles x2+y2 2ax+c2=0 and x2+y2 2by+c2=0 touch each …
Web4 apr. 2024 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site WebExpand (1) x2 + y2 – 2ax – 2by + a2 + b2 – r2 = 0. hence the general equation of the circle is taken as x2 + y2 + 2gx + 2fy + c = 0. .... (2) 2 This can be written as (x + g)2 + (y + f)2 = g 2 f 2 c 1 1 hence, Centre (–g, – f) i.e. ( – coefficient of x ; … plymouth bmd
The circle $x^{2}+y^{2}+2ax+c=0$ and $x^{2}+y^{2}+2by+c=0
Web(1) Comparing the equation x 2 + y 2 – 3x + 2y = 0 with x 2 + y 2 + 2gx + 2fy + c = 0, we get, 2g= –3, 2f = 2 and c = 0 ∴ g = f and c - 3 2, f = 1 and c = 0 ∴ from (1), the equation of the tangent to the given circle at the origin (0, 0) is x ( 0) + y ( 0) - 3 2 ( x + 0) + 1 ( y + 0) + 0 = 0 ∴ - 3 2 x + y = 0. ∴ 3x – 2y = 0. Concept: Tangent WebIf the Circles X2 + Y2 = 9 and X2 + Y2 + 8y + C = 0 Touch Each Other, Then C is Equal to - Mathematics. Advertisement Remove all ads. Advertisement Remove all ads. ... The … WebSince two circles are touching each other the common tangent will be the radical axis, and the equation of the radical axis we can write -. S = S'. x2+y2+2ax+c= x2+y2+2by+c =0. … pringles clicks